- FIRST_VALUE/LAST_VALUE分析函数的10g语法描述
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions057.htm#i83212
FIRST_VALUE (expr [ IGNORE NULLS ])
OVER (analytic_clause)
- 分析函数FIRST_VALUE可以非常便利并迅速的的得到排序后的第一条数据的各种信息
有关分析函数的扩展可以参考Oracle的官方文档中的“Analytic Functions”描述:http://download.oracle.com/docs/cd/B19306_01/server.102 /b14200/functions001.htm#SQLRF06174
- 通过调整order by的顺序可以取得最大最小值
- last_value与first_value同理
- FIRST_VALUE的使用方法
-- 创建测试表T,并初始化9条数据
create table t (group_id number(10), name varchar2(10), salary int);
insert into t values (1,'Tom',1200);
insert into t values (2,'Kary',2400);
insert into t values (2,'Joe',800);
insert into t values (3,'Andy',100);
insert into t values (3,'Ellen',200);
insert into t values (3,'Erick',300);
insert into t values (3,'Hou',400);
insert into t values (3,'Mary',500);
insert into t values (3,'Secooler',600);
commit;
-- T表全貌
-- 共三组数据,group_id分别是1、2和3。第1组有一个人,第2组有两个人,第3组有六个人。最后一列是每个人的薪水值
sec@ora10g> select * from t order by group_id,name;
GROUP_ID NAME SALARY
---------- ------------------------------ ----------
1 Tom 1200
2 Joe 800
2 Kary 2400
3 Andy 100
3 Ellen 200
3 Erick 300
3 Hou 400
3 Mary 500
3 Secooler 600
9 rows selected.
-- 在T表中添加一列,标识每一个数据分区中薪水最低的人名
select group_id, name, salary, FIRST_VALUE(name) OVER (partition by group_id order by salary asc ) as lowest_sal_name from t order by group_id, name;
or
select group_id, name, salary, FIRST_VALUE(name) OVER (partition by group_id order by salary asc ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) as lowest_sal_name from t order by group_id, name;
GROUP_ID NAME SALARY LOWEST_SAL
---------- ------------------------------ ---------- ----------
1 Tom 1200 Tom
2 Joe 800 Joe
2 Kary 2400 Joe
3 Andy 100 Andy
3 Ellen 200 Andy
3 Erick 300 Andy
3 Hou 400 Andy
3 Mary 500 Andy
3 Secooler 600 Andy
9 rows selected.
-- 在T表中添加一列,标识每一个数据分区中薪水最低的薪水值
select group_id, name, salary, FIRST_VALUE(SALARY) OVER (partition by group_id order by salary asc ) as lowest_sal_name from t order by group_id, name;
or
select group_id, name, salary, FIRST_VALUE(SALARY) OVER (partition by group_id order by salary asc ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) as lowest_sal_name from t order by group_id, name;
GROUP_ID NAME SALARY LOWEST_SAL_NAME
---------- ------------------------------ ---------- ---------------
1 Tom 1200 1200
2 Joe 800 800
2 Kary 2400 800
3 Andy 100 100
3 Ellen 200 100
3 Erick 300 100
3 Hou 400 100
3 Mary 500 100
3 Secooler 600 100
9 rows selected.
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